(2x+6)(x+7)=2x2^

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Solution for (2x+6)(x+7)=2x2^ equation: 



(2x+6)(x+7)=2x^2^

We move all terms to the left:

(2x+6)(x+7)-(2x^2^)=0

determiningTheFunctionDomain
-2x^2^+(2x+6)(x+7)=0

We multiply parentheses ..

-2x^2^+(+2x^2+14x+6x+42)=0

We get rid of parentheses

-2x^2^+2x^2+14x+6x+42=0

We add all the numbers together, and all the variables

2x^2-2x^2^+20x+42=0

We move all terms containing x to the left, all other terms to the right

2x^2-2x^2^+20x=-42

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